In the redox reaction MnO4- + 5 Fe2+ + 8 H+ → Mn2+ + 5 Fe3+ + 4 H2O, how many electrons are transferred?

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Multiple Choice

In the redox reaction MnO4- + 5 Fe2+ + 8 H+ → Mn2+ + 5 Fe3+ + 4 H2O, how many electrons are transferred?

Explanation:
Electron transfer in redox reactions is about how many electrons move from the species being oxidized to the species being reduced. Here, permanganate is reduced from MnO4− (Mn on +7) to Mn2+ (Mn on +2), a gain of 5 electrons. At the same time, five Fe2+ ions are each oxidized to Fe3+, losing one electron apiece, for a total of 5 electrons donated. The number of electrons gained must equal the number donated, so the total transferred is 5. The other numbers would not balance the electron flow in this reaction.

Electron transfer in redox reactions is about how many electrons move from the species being oxidized to the species being reduced. Here, permanganate is reduced from MnO4− (Mn on +7) to Mn2+ (Mn on +2), a gain of 5 electrons. At the same time, five Fe2+ ions are each oxidized to Fe3+, losing one electron apiece, for a total of 5 electrons donated. The number of electrons gained must equal the number donated, so the total transferred is 5. The other numbers would not balance the electron flow in this reaction.

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