In a gas mixture at STP, what volume does 0.50 moles of an ideal gas occupy?

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Multiple Choice

In a gas mixture at STP, what volume does 0.50 moles of an ideal gas occupy?

Explanation:
At STP, the volume occupied by an ideal gas is 22.4 liters per mole. So for 0.50 moles, multiply: 22.4 × 0.50 = 11.2 L. Therefore, the gas would take up 11.2 liters. This is half of the 22.4 L per mole, which matches having half a mole. (For reference, 22.4 L corresponds to 1 mole, 44.8 L to 2 moles, and 5.6 L to 0.25 mole.)

At STP, the volume occupied by an ideal gas is 22.4 liters per mole. So for 0.50 moles, multiply: 22.4 × 0.50 = 11.2 L. Therefore, the gas would take up 11.2 liters. This is half of the 22.4 L per mole, which matches having half a mole. (For reference, 22.4 L corresponds to 1 mole, 44.8 L to 2 moles, and 5.6 L to 0.25 mole.)

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