If 58.44 g of NaCl is dissolved in enough water to make 1.50 L of solution, what is the final molarity?

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Multiple Choice

If 58.44 g of NaCl is dissolved in enough water to make 1.50 L of solution, what is the final molarity?

Explanation:
Concentration in molarity is moles of solute per liter of solution. Convert the mass of NaCl to moles using its molar mass (NaCl is 58.44 g/mol). The 58.44 g given corresponds to 1.00 mole. The solution volume is 1.50 L, so the molarity is 1.00 mol ÷ 1.50 L = 0.6667 M. Therefore, the final molarity is 0.6667 M.

Concentration in molarity is moles of solute per liter of solution. Convert the mass of NaCl to moles using its molar mass (NaCl is 58.44 g/mol). The 58.44 g given corresponds to 1.00 mole. The solution volume is 1.50 L, so the molarity is 1.00 mol ÷ 1.50 L = 0.6667 M. Therefore, the final molarity is 0.6667 M.

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