At STP, what is the density in g/L of a gas with molar mass 22.4 g/mol?

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Multiple Choice

At STP, what is the density in g/L of a gas with molar mass 22.4 g/mol?

Explanation:
At STP, one mole of an ideal gas occupies 22.4 L. Density is mass per volume, so for a gas with molar mass 22.4 g/mol, the mass of one mole is 22.4 g and it fills 22.4 L. The density is 22.4 g ÷ 22.4 L = 1.0 g/L. This follows the relation ρ = M/22.4, since ρ = PM/RT and at STP P and T give the 22.4 L/mol molar volume. The other numbers would correspond to different molar masses, but with this molar mass the density comes out to 1.0 g/L.

At STP, one mole of an ideal gas occupies 22.4 L. Density is mass per volume, so for a gas with molar mass 22.4 g/mol, the mass of one mole is 22.4 g and it fills 22.4 L. The density is 22.4 g ÷ 22.4 L = 1.0 g/L. This follows the relation ρ = M/22.4, since ρ = PM/RT and at STP P and T give the 22.4 L/mol molar volume. The other numbers would correspond to different molar masses, but with this molar mass the density comes out to 1.0 g/L.

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