At STP, one mole of an ideal gas occupies what volume?

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Multiple Choice

At STP, one mole of an ideal gas occupies what volume?

Explanation:
At STP, one mole of an ideal gas has a fixed molar volume due to PV = nRT. With P = 1 atm, T = 273.15 K, n = 1 mol, and R = 0.0821 L·atm/(mol·K), the volume is V = nRT/P = (1)(0.0821)(273.15)/1 ≈ 22.4 L. So the correct volume is about 22.4 liters. The other numbers correspond to different conditions (for example, roughly 24 L at around room temperature, not STP).

At STP, one mole of an ideal gas has a fixed molar volume due to PV = nRT. With P = 1 atm, T = 273.15 K, n = 1 mol, and R = 0.0821 L·atm/(mol·K), the volume is V = nRT/P = (1)(0.0821)(273.15)/1 ≈ 22.4 L. So the correct volume is about 22.4 liters. The other numbers correspond to different conditions (for example, roughly 24 L at around room temperature, not STP).

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